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log trendline formula
This is a log trendline formula from Excel semilog graphing.
y = 0.8065Ln(x) + 3.4412 can anyone tell me how the " 0.8065Ln(x) " part of this formula works? I know y and i am solving for "x" not sure the significance of the "Ln" do i have to use some "log" function? -- dr chuck |
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