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I have a list of 3288 items, I want to find the median of FCFY those items with a p/e value greater than one. There are 2 columns: p/e value and FCFY.
I think the formula should look like this but it doesn't work.. =IF(B4:B32881,MEDIAN(C4:C3288)) English: Find the median of C's value for all B's that are greater than 1. Thanks for your help!! |
#2
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![]() Quote:
Try this one: =MEDIAN(IF(B4:B32881:C4:C3288)) This is a MATRICIAL FORMULA. ATTENTION: Don´t type ENTER after to type the fórmula. TYPE: SHIFT + CTRL + ENTER After it the formula will looks like this: {=MEDIAN(IF(B4:B32881:C4:C3288))} Teel me if it worked for you. Fell free to ask anything about it.
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I hope it can help you. Best regards, Marcilio Lobão --------------------------- Belo Horizonte, Brazil |
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