#1   Report Post  
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Default MIN ARRAY FORMULA


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column I even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman
  #2   Report Post  
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Posts: 3,572
Default MIN ARRAY FORMULA

I'm assuming that you want the cell address of the minimum value in a
column.

Since your dealing with a single, *known* column (Column I), I don't
understand why your calculating the second argument of the Address()
function.
Simply plug in "9" for the ninth column which is "I".

If my assumptions are correct, this should work for you:

=ADDRESS(MATCH(SMALL(I9:I373,COUNTIF(I9:I373,0)+1) ,I9:I373,0)+8,9)
--
HTH,

RD

---------------------------------------------------------------------------
Please keep all correspondence within the NewsGroup, so all may benefit !
---------------------------------------------------------------------------

"bookman3" wrote in message
...

Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column I even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman



  #3   Report Post  
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Posts: 25
Default MIN ARRAY FORMULA

Hi

That works a treat.

I have 2 supplementary questions

If the same minimum value appears more than once in the list,how can I find
the last entry?

I replaced SMALL with MAX. That worked but if there are more than 2 maximum
values in the list, how can I find the last entry?
--
bookman


"bookman3" wrote:


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column I even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman

  #4   Report Post  
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Posts: 15,768
Default MIN ARRAY FORMULA

Are your numbers sorted in descending order?

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
Hi

That works a treat.

I have 2 supplementary questions

If the same minimum value appears more than once in the list,how can I
find
the last entry?

I replaced SMALL with MAX. That worked but if there are more than 2
maximum
values in the list, how can I find the last entry?
--
bookman


"bookman3" wrote:


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column I even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman



  #5   Report Post  
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Posts: 25
Default MIN ARRAY FORMULA

No the nmubers are random, actually the column to the left is in date order
and this column has the amount relating to that date
--
bookman


"T. Valko" wrote:

Are your numbers sorted in descending order?

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
Hi

That works a treat.

I have 2 supplementary questions

If the same minimum value appears more than once in the list,how can I
find
the last entry?

I replaced SMALL with MAX. That worked but if there are more than 2
maximum
values in the list, how can I find the last entry?
--
bookman


"bookman3" wrote:


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column I even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman






  #6   Report Post  
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Posts: 15,768
Default MIN ARRAY FORMULA

Ok, do you specifically need the cell address or do want the actual number
but the only way you know how to find it is by using the address formula?

We can do either one.

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
No the nmubers are random, actually the column to the left is in date
order
and this column has the amount relating to that date
--
bookman


"T. Valko" wrote:

Are your numbers sorted in descending order?

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
Hi

That works a treat.

I have 2 supplementary questions

If the same minimum value appears more than once in the list,how can I
find
the last entry?

I replaced SMALL with MAX. That worked but if there are more than 2
maximum
values in the list, how can I find the last entry?
--
bookman


"bookman3" wrote:


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column I
even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman






  #7   Report Post  
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Posts: 25
Default MIN ARRAY FORMULA

I know the values, I just want to display the cell references of the latest
largest and smallest values, ignoring zeros as the zero values are next to
future dates
--
bookman


"T. Valko" wrote:

Ok, do you specifically need the cell address or do want the actual number
but the only way you know how to find it is by using the address formula?

We can do either one.

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
No the nmubers are random, actually the column to the left is in date
order
and this column has the amount relating to that date
--
bookman


"T. Valko" wrote:

Are your numbers sorted in descending order?

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
Hi

That works a treat.

I have 2 supplementary questions

If the same minimum value appears more than once in the list,how can I
find
the last entry?

I replaced SMALL with MAX. That worked but if there are more than 2
maximum
values in the list, how can I find the last entry?
--
bookman


"bookman3" wrote:


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column I
even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman






  #8   Report Post  
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Posts: 15,768
Default MIN ARRAY FORMULA

Ok, I'm assuming that latest means the furthest down the column. Like this:

A1 = 90
A2 = 5
A3 = 90
A4 = 5

Max address would be A3. Min address would be A4

Address for the max:

=ADDRESS(LOOKUP(2,1/(I9:I373=MAX(I9:I373)),ROW(I9:I373)),9,4)

Address for the min:

Array entered**

=ADDRESS(MAX(IF(I9:I373=MIN(IF(I9:I3730,I9:I373)) ,ROW(I9:I373))),9,4)

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT
key then hit ENTER.

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
I know the values, I just want to display the cell references of the latest
largest and smallest values, ignoring zeros as the zero values are next to
future dates
--
bookman


"T. Valko" wrote:

Ok, do you specifically need the cell address or do want the actual
number
but the only way you know how to find it is by using the address formula?

We can do either one.

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
No the nmubers are random, actually the column to the left is in date
order
and this column has the amount relating to that date
--
bookman


"T. Valko" wrote:

Are your numbers sorted in descending order?

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
Hi

That works a treat.

I have 2 supplementary questions

If the same minimum value appears more than once in the list,how can
I
find
the last entry?

I replaced SMALL with MAX. That worked but if there are more than 2
maximum
values in the list, how can I find the last entry?
--
bookman


"bookman3" wrote:


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column
I
even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman








  #9   Report Post  
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Posts: 3,572
Default MIN ARRAY FORMULA

Both are *array* formulas.

For *last* minimum entry:

=ADDRESS(MAX((I9:I373=MIN(I9:I30))*ROW(I9:I373)),9 )

For *last* maximum entry:

=ADDRESS(MAX((I9:I373=MAX(I9:I30))*ROW(I9:I373)),9 )


--
Array formulas are entered using CSE, <Ctrl <Shift <Enter, instead of the
regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually. Also, CSE *must* be used when
revising the formula.

--

HTH,

RD
================================================== ===
Please keep all correspondence within the Group, so all may benefit!
================================================== ===

"bookman3" wrote in message
...
I know the values, I just want to display the cell references of the latest
largest and smallest values, ignoring zeros as the zero values are next to
future dates
--
bookman


"T. Valko" wrote:

Ok, do you specifically need the cell address or do want the actual number
but the only way you know how to find it is by using the address formula?

We can do either one.

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
No the nmubers are random, actually the column to the left is in date
order
and this column has the amount relating to that date
--
bookman


"T. Valko" wrote:

Are your numbers sorted in descending order?

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
Hi

That works a treat.

I have 2 supplementary questions

If the same minimum value appears more than once in the list,how can
I
find
the last entry?

I replaced SMALL with MAX. That worked but if there are more than 2
maximum
values in the list, how can I find the last entry?
--
bookman


"bookman3" wrote:


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column I
even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman








  #10   Report Post  
Posted to microsoft.public.excel.misc
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Posts: 3,572
Default MIN ARRAY FORMULA

*TYPOS*

Both are *array* formulas.

For *last* minimum entry:

=ADDRESS(MAX((I9:I373=MIN(I9:I373))*ROW(I9:I373)), 9)

For *last* maximum entry:

=ADDRESS(MAX((I9:I373=MAX(I9:I373))*ROW(I9:I373)), 9)
--
Array formulas are entered using CSE, <Ctrl <Shift <Enter, instead of the
regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually. Also, CSE *must* be used when
revising the formula.

--

HTH,

RD
================================================== ===
Please keep all correspondence within the Group, so all may benefit!
================================================== ===


"RagDyeR" wrote in message
...
Both are *array* formulas.

For *last* minimum entry:

=ADDRESS(MAX((I9:I373=MIN(I9:I30))*ROW(I9:I373)),9 )

For *last* maximum entry:

=ADDRESS(MAX((I9:I373=MAX(I9:I30))*ROW(I9:I373)),9 )


--
Array formulas are entered using CSE, <Ctrl <Shift <Enter, instead of the
regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually. Also, CSE *must* be used when
revising the formula.

--

HTH,

RD
================================================== ===
Please keep all correspondence within the Group, so all may benefit!
================================================== ===

"bookman3" wrote in message
...
I know the values, I just want to display the cell references of the latest
largest and smallest values, ignoring zeros as the zero values are next to
future dates
--
bookman


"T. Valko" wrote:

Ok, do you specifically need the cell address or do want the actual number
but the only way you know how to find it is by using the address formula?

We can do either one.

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
No the nmubers are random, actually the column to the left is in date
order
and this column has the amount relating to that date
--
bookman


"T. Valko" wrote:

Are your numbers sorted in descending order?

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
Hi

That works a treat.

I have 2 supplementary questions

If the same minimum value appears more than once in the list,how can
I
find
the last entry?

I replaced SMALL with MAX. That worked but if there are more than 2
maximum
values in the list, how can I find the last entry?
--
bookman


"bookman3" wrote:


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column I
even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman











  #11   Report Post  
Posted to microsoft.public.excel.misc
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Posts: 3,572
Default MIN ARRAY FORMULA

*BAD* morning -

Correction for *last* minimum entry:

=ADDRESS(MAX((I9:I373=SMALL(I9:I373,COUNTIF(I9:I37 3,0)+1))*ROW(I9:I373)),9)
--
Array formulas are entered using CSE, <Ctrl <Shift <Enter, instead of the
regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually. Also, CSE *must* be used when
revising the formula.

--

Regards,

RD
-----------------------------------------------------------------------------------------------
Please keep all correspondence within the Group, so all may benefit !
-----------------------------------------------------------------------------------------------


"RagDyeR" wrote in message
...
*TYPOS*

Both are *array* formulas.

For *last* minimum entry:

=ADDRESS(MAX((I9:I373=MIN(I9:I373))*ROW(I9:I373)), 9)

For *last* maximum entry:

=ADDRESS(MAX((I9:I373=MAX(I9:I373))*ROW(I9:I373)), 9)
--
Array formulas are entered using CSE, <Ctrl <Shift <Enter, instead of the
regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually. Also, CSE *must* be used when
revising the formula.

--

HTH,

RD
================================================== ===
Please keep all correspondence within the Group, so all may benefit!
================================================== ===


"RagDyeR" wrote in message
...
Both are *array* formulas.

For *last* minimum entry:

=ADDRESS(MAX((I9:I373=MIN(I9:I30))*ROW(I9:I373)),9 )

For *last* maximum entry:

=ADDRESS(MAX((I9:I373=MAX(I9:I30))*ROW(I9:I373)),9 )


--
Array formulas are entered using CSE, <Ctrl <Shift <Enter, instead of the
regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually. Also, CSE *must* be used when
revising the formula.

--

HTH,

RD
================================================== ===
Please keep all correspondence within the Group, so all may benefit!
================================================== ===

"bookman3" wrote in message
...
I know the values, I just want to display the cell references of the latest
largest and smallest values, ignoring zeros as the zero values are next to
future dates
--
bookman


"T. Valko" wrote:

Ok, do you specifically need the cell address or do want the actual number
but the only way you know how to find it is by using the address formula?

We can do either one.

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
No the nmubers are random, actually the column to the left is in date
order
and this column has the amount relating to that date
--
bookman


"T. Valko" wrote:

Are your numbers sorted in descending order?

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
Hi

That works a treat.

I have 2 supplementary questions

If the same minimum value appears more than once in the list,how can
I
find
the last entry?

I replaced SMALL with MAX. That worked but if there are more than 2
maximum
values in the list, how can I find the last entry?
--
bookman


"bookman3" wrote:


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column I
even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman










  #12   Report Post  
Posted to microsoft.public.excel.misc
external usenet poster
 
Posts: 15,768
Default MIN ARRAY FORMULA

For *last* minimum entry:
=ADDRESS(MAX((I9:I373=MIN(I9:I373))*ROW(I9:I373)) ,9)


That won't exclude 0s.


--
Biff
Microsoft Excel MVP


"RagDyeR" wrote in message
...
*TYPOS*

Both are *array* formulas.

For *last* minimum entry:

=ADDRESS(MAX((I9:I373=MIN(I9:I373))*ROW(I9:I373)), 9)

For *last* maximum entry:

=ADDRESS(MAX((I9:I373=MAX(I9:I373))*ROW(I9:I373)), 9)
--
Array formulas are entered using CSE, <Ctrl <Shift <Enter, instead of
the
regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually. Also, CSE *must* be used when
revising the formula.

--

HTH,

RD
================================================== ===
Please keep all correspondence within the Group, so all may benefit!
================================================== ===


"RagDyeR" wrote in message
...
Both are *array* formulas.

For *last* minimum entry:

=ADDRESS(MAX((I9:I373=MIN(I9:I30))*ROW(I9:I373)),9 )

For *last* maximum entry:

=ADDRESS(MAX((I9:I373=MAX(I9:I30))*ROW(I9:I373)),9 )


--
Array formulas are entered using CSE, <Ctrl <Shift <Enter, instead of
the
regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually. Also, CSE *must* be used when
revising the formula.

--

HTH,

RD
================================================== ===
Please keep all correspondence within the Group, so all may benefit!
================================================== ===

"bookman3" wrote in message
...
I know the values, I just want to display the cell references of the
latest
largest and smallest values, ignoring zeros as the zero values are next to
future dates
--
bookman


"T. Valko" wrote:

Ok, do you specifically need the cell address or do want the actual
number
but the only way you know how to find it is by using the address formula?

We can do either one.

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
No the nmubers are random, actually the column to the left is in date
order
and this column has the amount relating to that date
--
bookman


"T. Valko" wrote:

Are your numbers sorted in descending order?

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
Hi

That works a treat.

I have 2 supplementary questions

If the same minimum value appears more than once in the list,how can
I
find
the last entry?

I replaced SMALL with MAX. That worked but if there are more than 2
maximum
values in the list, how can I find the last entry?
--
bookman


"bookman3" wrote:


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column
I
even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman











  #13   Report Post  
Posted to microsoft.public.excel.misc
external usenet poster
 
Posts: 3,572
Default MIN ARRAY FORMULA

I'll assume by now, you've seen my last *VERY BAD MORNING* revision!

Tough to prioritize time when two transformers go at the same time.<bg
--
Regards,

RD

---------------------------------------------------------------------------
Please keep all correspondence within the NewsGroup, so all may benefit !
---------------------------------------------------------------------------
"T. Valko" wrote in message
...
For *last* minimum entry:
=ADDRESS(MAX((I9:I373=MIN(I9:I373))*ROW(I9:I373) ),9)


That won't exclude 0s.


--
Biff
Microsoft Excel MVP


"RagDyeR" wrote in message
...
*TYPOS*

Both are *array* formulas.

For *last* minimum entry:

=ADDRESS(MAX((I9:I373=MIN(I9:I373))*ROW(I9:I373)), 9)

For *last* maximum entry:

=ADDRESS(MAX((I9:I373=MAX(I9:I373))*ROW(I9:I373)), 9)
--
Array formulas are entered using CSE, <Ctrl <Shift <Enter, instead of
the
regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually. Also, CSE *must* be used when
revising the formula.

--

HTH,

RD
================================================== ===
Please keep all correspondence within the Group, so all may benefit!
================================================== ===


"RagDyeR" wrote in message
...
Both are *array* formulas.

For *last* minimum entry:

=ADDRESS(MAX((I9:I373=MIN(I9:I30))*ROW(I9:I373)),9 )

For *last* maximum entry:

=ADDRESS(MAX((I9:I373=MAX(I9:I30))*ROW(I9:I373)),9 )


--
Array formulas are entered using CSE, <Ctrl <Shift <Enter, instead of
the
regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually. Also, CSE *must* be used when
revising the formula.

--

HTH,

RD
================================================== ===
Please keep all correspondence within the Group, so all may benefit!
================================================== ===

"bookman3" wrote in message
...
I know the values, I just want to display the cell references of the
latest
largest and smallest values, ignoring zeros as the zero values are next
to
future dates
--
bookman


"T. Valko" wrote:

Ok, do you specifically need the cell address or do want the actual
number
but the only way you know how to find it is by using the address
formula?

We can do either one.

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
No the nmubers are random, actually the column to the left is in date
order
and this column has the amount relating to that date
--
bookman


"T. Valko" wrote:

Are your numbers sorted in descending order?

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
Hi

That works a treat.

I have 2 supplementary questions

If the same minimum value appears more than once in the list,how
can
I
find
the last entry?

I replaced SMALL with MAX. That worked but if there are more than 2
maximum
values in the list, how can I find the last entry?
--
bookman


"bookman3" wrote:


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in column
I
even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman













  #14   Report Post  
Posted to microsoft.public.excel.misc
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Posts: 15,768
Default MIN ARRAY FORMULA

Tough to prioritize time when two transformers go at the same time.<bg

I can relate!

--
Biff
Microsoft Excel MVP


"RagDyer" wrote in message
...
I'll assume by now, you've seen my last *VERY BAD MORNING* revision!

Tough to prioritize time when two transformers go at the same time.<bg
--
Regards,

RD

---------------------------------------------------------------------------
Please keep all correspondence within the NewsGroup, so all may benefit !
---------------------------------------------------------------------------
"T. Valko" wrote in message
...
For *last* minimum entry:
=ADDRESS(MAX((I9:I373=MIN(I9:I373))*ROW(I9:I373 )),9)


That won't exclude 0s.


--
Biff
Microsoft Excel MVP


"RagDyeR" wrote in message
...
*TYPOS*

Both are *array* formulas.

For *last* minimum entry:

=ADDRESS(MAX((I9:I373=MIN(I9:I373))*ROW(I9:I373)), 9)

For *last* maximum entry:

=ADDRESS(MAX((I9:I373=MAX(I9:I373))*ROW(I9:I373)), 9)
--
Array formulas are entered using CSE, <Ctrl <Shift <Enter, instead of
the
regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually. Also, CSE *must* be used
when
revising the formula.

--

HTH,

RD
================================================== ===
Please keep all correspondence within the Group, so all may benefit!
================================================== ===


"RagDyeR" wrote in message
...
Both are *array* formulas.

For *last* minimum entry:

=ADDRESS(MAX((I9:I373=MIN(I9:I30))*ROW(I9:I373)),9 )

For *last* maximum entry:

=ADDRESS(MAX((I9:I373=MAX(I9:I30))*ROW(I9:I373)),9 )


--
Array formulas are entered using CSE, <Ctrl <Shift <Enter, instead of
the
regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually. Also, CSE *must* be used
when
revising the formula.

--

HTH,

RD
================================================== ===
Please keep all correspondence within the Group, so all may benefit!
================================================== ===

"bookman3" wrote in message
...
I know the values, I just want to display the cell references of the
latest
largest and smallest values, ignoring zeros as the zero values are next
to
future dates
--
bookman


"T. Valko" wrote:

Ok, do you specifically need the cell address or do want the actual
number
but the only way you know how to find it is by using the address
formula?

We can do either one.

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
No the nmubers are random, actually the column to the left is in date
order
and this column has the amount relating to that date
--
bookman


"T. Valko" wrote:

Are your numbers sorted in descending order?

--
Biff
Microsoft Excel MVP


"bookman3" wrote in message
...
Hi

That works a treat.

I have 2 supplementary questions

If the same minimum value appears more than once in the list,how
can
I
find
the last entry?

I replaced SMALL with MAX. That worked but if there are more than
2
maximum
values in the list, how can I find the last entry?
--
bookman


"bookman3" wrote:


Hi

{=ADDRESS(MIN(IF($I$9:$I$373=MIN($I$9:$I$373)*($I$ 9:$I$373<0),ROW($I$9:$I$373))),MIN(IF($I$9:$I$373 =MIN($I$9:$I$373)*($I$9:$I$373<0),COLUMN($I$9:$I$ 373))))}

This formula only works fine except when there are zeros in
column I
even
though the formula is looking at vlaues < 0
For example: rows 9 to 84 have values, rows 85 to 373 have 0.
The formula gives the result of I85.
If rows 85 to 373 are left blank the result is correct.

Can anyone help?
--
bookman















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