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#1
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A1:A10 are numbers
A2 is another number A3 is a formula that states: the number of times A1:A10 is above A2 For example: 5 2 3 5 8 9 4 2 0 1 (numbers) 3 5 (# of times numbers are 3). thanks...! |
#2
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One way (assuming you meant A1:J1 rather than A1:A10, since otherwise
you'll get a circular reference): A3: =COUNTIF(A1:J1,"" & A2) In article , SteveC wrote: A1:A10 are numbers A2 is another number A3 is a formula that states: the number of times A1:A10 is above A2 For example: 5 2 3 5 8 9 4 2 0 1 (numbers) 3 5 (# of times numbers are 3). thanks...! |
#3
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I'm assuming you mean A1:J1? Try this:
=SUMPRODUCT(--(A1:J1A2)) HTH, Elkar "SteveC" wrote: A1:A10 are numbers A2 is another number A3 is a formula that states: the number of times A1:A10 is above A2 For example: 5 2 3 5 8 9 4 2 0 1 (numbers) 3 5 (# of times numbers are 3). thanks...! |
#4
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thanks, works great.
"JE McGimpsey" wrote: One way (assuming you meant A1:J1 rather than A1:A10, since otherwise you'll get a circular reference): A3: =COUNTIF(A1:J1,"" & A2) In article , SteveC wrote: A1:A10 are numbers A2 is another number A3 is a formula that states: the number of times A1:A10 is above A2 For example: 5 2 3 5 8 9 4 2 0 1 (numbers) 3 5 (# of times numbers are 3). thanks...! |
#5
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ah, that tricky sumproduct again. thanks!
"Elkar" wrote: I'm assuming you mean A1:J1? Try this: =SUMPRODUCT(--(A1:J1A2)) HTH, Elkar "SteveC" wrote: A1:A10 are numbers A2 is another number A3 is a formula that states: the number of times A1:A10 is above A2 For example: 5 2 3 5 8 9 4 2 0 1 (numbers) 3 5 (# of times numbers are 3). thanks...! |
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