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Sandy Mann Sandy Mann is offline
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Default Array function does not seem to work

I thought that you had adequately explained the reason in the other thread
Bob so I did not respond. However, because it was in *another thread* I
suppose that for completeness in the archives it did require an answer.

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


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"Bob Phillips" wrote in message
...
Because you have a continental version of Excel which uses comma as the
decimal separator, so semi-colon is used as the list separator. Our
English version is dot and comma.

--
---
HTH

Bob


(there's no email, no snail mail, but somewhere should be gmail in my
addy)



"dartanion" wrote in message
...
Thanks Sandy, I changed all the , to ; and the array works. WHY??

"Sandy Mann" wrote:

ctrl-shift-enter and an error came up and C1000,LARGE was
highlighted.

Do you use semi-colon separator or comma? If so change the , to ;

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"dartanion" wrote in message
...
Thanks Bernard, but no the same error appeared, which suggests to me
its
not
the formula, but something in excel, what do you think, and any ideas
what
I
can test?

"Bernard Liengme" wrote:

Not sure what you are doing but I wonder if the formula should be
=INDEX(C1:C1000,LARGE(IF(C1:C1000<"",ROW(C1:C1000 )),2))
the change being just after IF(
best wishes
--
Bernard V Liengme
Microsoft Excel MVP
www.stfx.ca/people/bliengme
remove caps from email

"dartanion" wrote in message
...
Over the last few days, I have sought and received help from the
community.
The help has been with formulas requiring array answers.
Each time I try the cntr-shift-enter, an error appears in the
middle of
the
formula. e.g Mike gave me this fomula
=INDEX(C1:C1000,LARGE(IF(C1000<"",ROW(C1:C1000)), 2)) I used the
ctrl-shift-enter and an error came up and C1000,LARGE was
highlighted.
I
then
went on to the array learning module, and entered an array formula
for
part
of that study, and again an error message appeared with a similar
part
of
their function highlighted as an error. Anyone suggest solution?